Search a number
-
+
1005240153 = 31811851271
BaseRepresentation
bin111011111010101…
…011111101011001
32121001112111020210
4323322223331121
54024320141103
6243425441333
733624254211
oct7372537531
92531474223
101005240153
11476482895
122407a0249
13130353378
1497713241
155d3b8e03
hex3beabf59

1005240153 has 8 divisors (see below), whose sum is σ = 1347726016. Its totient is φ = 666457200.

The previous prime is 1005240151. The next prime is 1005240157. The reversal of 1005240153 is 3510425001.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1005240153 - 21 = 1005240151 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1005240151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 925093 + ... + 926178.

It is an arithmetic number, because the mean of its divisors is an integer number (168465752).

Almost surely, 21005240153 is an apocalyptic number.

It is an amenable number.

1005240153 is a deficient number, since it is larger than the sum of its proper divisors (342485863).

1005240153 is a wasteful number, since it uses less digits than its factorization.

1005240153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1851455.

The product of its (nonzero) digits is 600, while the sum is 21.

The square root of 1005240153 is about 31705.5224369509. The cubic root of 1005240153 is about 1001.7436754953.

Adding to 1005240153 its reverse (3510425001), we get a palindrome (4515665154).

It can be divided in two parts, 10052 and 40153, that added together give a palindrome (50205).

The spelling of 1005240153 in words is "one billion, five million, two hundred forty thousand, one hundred fifty-three".

Divisors: 1 3 181 543 1851271 5553813 335080051 1005240153