100532510433 has 6 divisors (see below), whose sum is σ = 145213626194. Its totient is φ = 67021673616.

The previous prime is 100532510423. The next prime is 100532510447. The reversal of 100532510433 is 334015235001.

100532510433 is a `hidden beast` number, since 100 + 5 + 3 + 2 + 510 + 43 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 72246988944 + 28285521489 = 268788^2 + 168183^2 .

It is not a de Polignac number, because 100532510433 - 2⁶ = 100532510369 is a prime.

It is a super-2 number, since 2×100532510433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100532510397 and 100532510406.

It is not an unprimeable number, because it can be changed into a prime (100532510423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5585139460 + ... + 5585139477.

Almost surely, 2^100532510433 is an apocalyptic number.

It is an amenable number.

100532510433 is a deficient number, since it is larger than the sum of its proper divisors (44681115761).

100532510433 is a wasteful number, since it uses less digits than its factorization.

100532510433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11170278943 (or 11170278940 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 100532510433 its reverse (334015235001), we get a palindrome (434547745434).

The spelling of 100532510433 in words is "one hundred billion, five hundred thirty-two million, five hundred ten thousand, four hundred thirty-three".