10053660433 has 4 divisors (see below), whose sum is σ = 10490776128. Its totient is φ = 9616544740.

The previous prime is 10053660403. The next prime is 10053660467. The reversal of 10053660433 is 33406635001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10053660433 - 2⁹ = 10053659921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10053660395 and 10053660404.

It is not an unprimeable number, because it can be changed into a prime (10053660403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218557813 + ... + 218557858.

It is an arithmetic number, because the mean of its divisors is an integer number (2622694032).

Almost surely, 2^10053660433 is an apocalyptic number.

It is an amenable number.

10053660433 is a deficient number, since it is larger than the sum of its proper divisors (437115695).

10053660433 is an equidigital number, since it uses as much as digits as its factorization.

10053660433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437115694.

The product of its (nonzero) digits is 19440, while the sum is 31.

The spelling of 10053660433 in words is "ten billion, fifty-three million, six hundred sixty thousand, four hundred thirty-three".