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10055000593 = 11914090963
BaseRepresentation
bin10010101110101001…
…10010001000010001
3221221202020221202101
421113110302020101
5131043040004333
64341425320401
7504113044351
oct112724621021
927852227671
1010055000593
11429a870850
121b47496101
13c432069c1
146b559cb61
153dcb2467d
hex257532211

10055000593 has 4 divisors (see below), whose sum is σ = 10969091568. Its totient is φ = 9140909620.

The previous prime is 10055000587. The next prime is 10055000603. The reversal of 10055000593 is 39500055001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10055000593 is a prime.

It is a super-2 number, since 2×100550005932 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10055000563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 457045471 + ... + 457045492.

It is an arithmetic number, because the mean of its divisors is an integer number (2742272892).

Almost surely, 210055000593 is an apocalyptic number.

It is an amenable number.

10055000593 is a deficient number, since it is larger than the sum of its proper divisors (914090975).

10055000593 is an equidigital number, since it uses as much as digits as its factorization.

10055000593 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 914090974.

The product of its (nonzero) digits is 3375, while the sum is 28.

Adding to 10055000593 its reverse (39500055001), we get a palindrome (49555055594).

The spelling of 10055000593 in words is "ten billion, fifty-five million, five hundred ninety-three", and thus it is an aban number.

Divisors: 1 11 914090963 10055000593