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10055251 = 13037717
BaseRepresentation
bin100110010110…
…111001010011
3200220212012201
4212112321103
510033232001
6555304031
7151316413
oct46267123
920825181
1010055251
115748728
12344b017
132110a6b
14149a643
15d39501
hex996e53

10055251 has 4 divisors (see below), whose sum is σ = 10064272. Its totient is φ = 10046232.

The previous prime is 10055219. The next prime is 10055263. The reversal of 10055251 is 15255001.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 10055251 - 25 = 10055219 is a prime.

It is a super-2 number, since 2×100552512 = 202216145346002, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10055281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2556 + ... + 5161.

It is an arithmetic number, because the mean of its divisors is an integer number (2516068).

Almost surely, 210055251 is an apocalyptic number.

10055251 is a deficient number, since it is larger than the sum of its proper divisors (9021).

10055251 is an equidigital number, since it uses as much as digits as its factorization.

10055251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9020.

The product of its (nonzero) digits is 250, while the sum is 19.

The square root of 10055251 is about 3171.0015767893. The cubic root of 10055251 is about 215.8395227210.

Subtracting from 10055251 its product of nonzero digits (250), we obtain a palindrome (10055001).

The spelling of 10055251 in words is "ten million, fifty-five thousand, two hundred fifty-one".

Divisors: 1 1303 7717 10055251