Search a number
-
+
1008141126913 = 2347429544579
BaseRepresentation
bin11101010101110011110…
…01001100110100000001
310120101012002101112010001
432222321321030310001
5113004133112030123
62051044511040001
7132556451121634
oct16527171146401
93511162345101
101008141126913
11359606425058
12143474510001
13740b4b21bbb
1436b19769c1b
151b35633c0ad
hexeab9e4cd01

1008141126913 has 4 divisors (see below), whose sum is σ = 1008570673840. Its totient is φ = 1007711579988.

The previous prime is 1008141126901. The next prime is 1008141126943. The reversal of 1008141126913 is 3196211418001.

1008141126913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1008141126913 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1008141126943) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214769943 + ... + 214774636.

It is an arithmetic number, because the mean of its divisors is an integer number (252142668460).

Almost surely, 21008141126913 is an apocalyptic number.

It is an amenable number.

1008141126913 is a deficient number, since it is larger than the sum of its proper divisors (429546927).

1008141126913 is an equidigital number, since it uses as much as digits as its factorization.

1008141126913 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 429546926.

The product of its (nonzero) digits is 10368, while the sum is 37.

The spelling of 1008141126913 in words is "one trillion, eight billion, one hundred forty-one million, one hundred twenty-six thousand, nine hundred thirteen".

Divisors: 1 2347 429544579 1008141126913