Base | Representation |
---|---|
bin | 11101010101110011110… |
… | …01001100110100000001 |
3 | 10120101012002101112010001 |
4 | 32222321321030310001 |
5 | 113004133112030123 |
6 | 2051044511040001 |
7 | 132556451121634 |
oct | 16527171146401 |
9 | 3511162345101 |
10 | 1008141126913 |
11 | 359606425058 |
12 | 143474510001 |
13 | 740b4b21bbb |
14 | 36b19769c1b |
15 | 1b35633c0ad |
hex | eab9e4cd01 |
1008141126913 has 4 divisors (see below), whose sum is σ = 1008570673840. Its totient is φ = 1007711579988.
The previous prime is 1008141126901. The next prime is 1008141126943. The reversal of 1008141126913 is 3196211418001.
1008141126913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1008141126913 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1008141126943) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 214769943 + ... + 214774636.
It is an arithmetic number, because the mean of its divisors is an integer number (252142668460).
Almost surely, 21008141126913 is an apocalyptic number.
It is an amenable number.
1008141126913 is a deficient number, since it is larger than the sum of its proper divisors (429546927).
1008141126913 is an equidigital number, since it uses as much as digits as its factorization.
1008141126913 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 429546926.
The product of its (nonzero) digits is 10368, while the sum is 37.
The spelling of 1008141126913 in words is "one trillion, eight billion, one hundred forty-one million, one hundred twenty-six thousand, nine hundred thirteen".
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