10100133303131 has 4 divisors (see below), whose sum is σ = 10116994962000. Its totient is φ = 10083271644264.

The previous prime is 10100133303109. The next prime is 10100133303167. The reversal of 10100133303131 is 13130333100101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10100133303131 - 2¹⁰ = 10100133302107 is a prime.

It is a super-2 number, since 2×10100133303131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10100133303181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8430828536 + ... + 8430829733.

It is an arithmetic number, because the mean of its divisors is an integer number (2529248740500).

Almost surely, 2^{10100133303131} is an apocalyptic number.

10100133303131 is a deficient number, since it is larger than the sum of its proper divisors (16861658869).

10100133303131 is an equidigital number, since it uses as much as digits as its factorization.

10100133303131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16861658868.

The product of its (nonzero) digits is 243, while the sum is 20.

Adding to 10100133303131 its reverse (13130333100101), we get a palindrome (23230466403232).

The spelling of 10100133303131 in words is "ten trillion, one hundred billion, one hundred thirty-three million, three hundred three thousand, one hundred thirty-one".