10100220131233 has 4 divisors (see below), whose sum is σ = 10100336032048. Its totient is φ = 10100104230420.

The previous prime is 10100220131219. The next prime is 10100220131249. The reversal of 10100220131233 is 33213102200101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10100220131233 is a prime.

It is a super-4 number, since 4×10100220131233⁴ (a number of 53 digits) contains 4444 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10100220131233.

It is not an unprimeable number, because it can be changed into a prime (10100220131033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57819591 + ... + 57994012.

It is an arithmetic number, because the mean of its divisors is an integer number (2525084008012).

Almost surely, 2^{10100220131233} is an apocalyptic number.

It is an amenable number.

10100220131233 is a deficient number, since it is larger than the sum of its proper divisors (115900815).

10100220131233 is an equidigital number, since it uses as much as digits as its factorization.

10100220131233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115900814.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10100220131233 its reverse (33213102200101), we get a palindrome (43313322331334).

The spelling of 10100220131233 in words is "ten trillion, one hundred billion, two hundred twenty million, one hundred thirty-one thousand, two hundred thirty-three".