1010022323131 has 4 divisors (see below), whose sum is σ = 1010024360752. Its totient is φ = 1010020285512.

The previous prime is 1010022323129. The next prime is 1010022323197. The reversal of 1010022323131 is 1313232200101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1010022323131 - 2¹ = 1010022323129 is a prime.

It is a super-2 number, since 2×1010022323131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1010022323099 and 1010022323108.

It is not an unprimeable number, because it can be changed into a prime (1010022329131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258625 + ... + 1444621.

It is an arithmetic number, because the mean of its divisors is an integer number (252506090188).

Almost surely, 2^{1010022323131} is an apocalyptic number.

1010022323131 is a deficient number, since it is larger than the sum of its proper divisors (2037621).

1010022323131 is an equidigital number, since it uses as much as digits as its factorization.

1010022323131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2037620.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1010022323131 its reverse (1313232200101), we get a palindrome (2323254523232).

The spelling of 1010022323131 in words is "one trillion, ten billion, twenty-two million, three hundred twenty-three thousand, one hundred thirty-one".