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101011122122113 = 721650396665081
BaseRepresentation
bin10110111101111001111100…
…000011010110110110000001
3111020122120100202222022001101
4112331321330003112312001
5101214431234230401423
6554455511402534401
730163545525314260
oct2675717403266601
9436576322868041
10101011122122113
112a2046380a1025
12b3b4770507401
134449400726c18
141ad2d704385d7
15ba27e76997ad
hex5bde7c0d6d81

101011122122113 has 8 divisors (see below), whose sum is σ = 115441353066240. Its totient is φ = 86580908838240.

The previous prime is 101011122122093. The next prime is 101011122122221. The reversal of 101011122122113 is 311221221110101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101011122122113 - 217 = 101011121991041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101011122122413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11822733 + ... + 18487813.

It is an arithmetic number, because the mean of its divisors is an integer number (14430169133280).

Almost surely, 2101011122122113 is an apocalyptic number.

It is an amenable number.

101011122122113 is a deficient number, since it is larger than the sum of its proper divisors (14430230944127).

101011122122113 is an equidigital number, since it uses as much as digits as its factorization.

101011122122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8830127.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 101011122122113 its reverse (311221221110101), we get a palindrome (412232343232214).

The spelling of 101011122122113 in words is "one hundred one trillion, eleven billion, one hundred twenty-two million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 7 2165039 6665081 15155273 46655567 14430160303159 101011122122113