10102033113 has 8 divisors (see below), whose sum is σ = 14055002688. Its totient is φ = 6441876144.

The previous prime is 10102033103. The next prime is 10102033133. The reversal of 10102033113 is 31133020101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10102033113 - 2⁶ = 10102033049 is a prime.

It is a super-2 number, since 2×10102033113² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10102033092 and 10102033101.

It is not an unprimeable number, because it can be changed into a prime (10102033103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73203070 + ... + 73203207.

It is an arithmetic number, because the mean of its divisors is an integer number (1756875336).

Almost surely, 2^10102033113 is an apocalyptic number.

It is an amenable number.

10102033113 is a deficient number, since it is larger than the sum of its proper divisors (3952969575).

10102033113 is a wasteful number, since it uses less digits than its factorization.

10102033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146406303.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10102033113 its reverse (31133020101), we get a palindrome (41235053214).

The spelling of 10102033113 in words is "ten billion, one hundred two million, thirty-three thousand, one hundred thirteen".