Base | Representation |
---|---|
bin | 10010110100010000… |
… | …01111001100110001 |
3 | 222002000202222102002 |
4 | 21122020033030301 |
5 | 131142110342231 |
6 | 4350225503345 |
7 | 505223644460 |
oct | 113210171461 |
9 | 28060688362 |
10 | 10102043441 |
11 | 4314381836 |
12 | 1b5b1a1b55 |
13 | c4cb980c9 |
14 | 6bb9269d7 |
15 | 3e1d180cb |
hex | 25a20f331 |
10102043441 has 4 divisors (see below), whose sum is σ = 11545192512. Its totient is φ = 8658894372.
The previous prime is 10102043383. The next prime is 10102043477. The reversal of 10102043441 is 14434020101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14434020101 = 57493 ⋅251057.
It is a cyclic number.
It is not a de Polignac number, because 10102043441 - 214 = 10102027057 is a prime.
It is a super-2 number, since 2×101020434412 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10102043741) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 721574525 + ... + 721574538.
It is an arithmetic number, because the mean of its divisors is an integer number (2886298128).
Almost surely, 210102043441 is an apocalyptic number.
It is an amenable number.
10102043441 is a deficient number, since it is larger than the sum of its proper divisors (1443149071).
10102043441 is an equidigital number, since it uses as much as digits as its factorization.
10102043441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1443149070.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 10102043441 its reverse (14434020101), we get a palindrome (24536063542).
The spelling of 10102043441 in words is "ten billion, one hundred two million, forty-three thousand, four hundred forty-one".
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