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10102222113 = 33367407371
BaseRepresentation
bin10010110100010001…
…11010110100100001
3222002001010001111120
421122020322310201
5131142132101423
64350233402453
7505225320414
oct113210726441
928061101446
1010102222113
114314493aa5
121b5b269429
13c4cc2b529
146bb971b7b
153e1d50ee3
hex25a23ad21

10102222113 has 4 divisors (see below), whose sum is σ = 13469629488. Its totient is φ = 6734814740.

The previous prime is 10102222099. The next prime is 10102222121. The reversal of 10102222113 is 31122220101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10102222113 - 212 = 10102218017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10102222092 and 10102222101.

It is not an unprimeable number, because it can be changed into a prime (10102222153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1683703683 + ... + 1683703688.

It is an arithmetic number, because the mean of its divisors is an integer number (3367407372).

Almost surely, 210102222113 is an apocalyptic number.

It is an amenable number.

10102222113 is a deficient number, since it is larger than the sum of its proper divisors (3367407375).

10102222113 is an equidigital number, since it uses as much as digits as its factorization.

10102222113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3367407374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10102222113 its reverse (31122220101), we get a palindrome (41224442214).

The spelling of 10102222113 in words is "ten billion, one hundred two million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 3 3367407371 10102222113