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10103113321 = 71443301903
BaseRepresentation
bin10010110100011000…
…10100011001101001
3222002002210100000021
421122030110121221
5131142344111241
64350304440441
7505236021610
oct113214243151
928062710007
1010103113321
114314a42634
121b5b619121
13c50181082
146bbb24877
153e1e7a0d1
hex25a314669

10103113321 has 4 divisors (see below), whose sum is σ = 11546415232. Its totient is φ = 8659811412.

The previous prime is 10103113309. The next prime is 10103113387. The reversal of 10103113321 is 12331130101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10103113321 - 215 = 10103080553 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10103113295 and 10103113304.

It is not an unprimeable number, because it can be changed into a prime (10103113121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 721650945 + ... + 721650958.

It is an arithmetic number, because the mean of its divisors is an integer number (2886603808).

Almost surely, 210103113321 is an apocalyptic number.

It is an amenable number.

10103113321 is a deficient number, since it is larger than the sum of its proper divisors (1443301911).

10103113321 is an equidigital number, since it uses as much as digits as its factorization.

10103113321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1443301910.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10103113321 its reverse (12331130101), we get a palindrome (22434243422).

The spelling of 10103113321 in words is "ten billion, one hundred three million, one hundred thirteen thousand, three hundred twenty-one".

Divisors: 1 7 1443301903 10103113321