1010312631113 has 4 divisors (see below), whose sum is σ = 1010614490640. Its totient is φ = 1010010771588.

The previous prime is 1010312631109. The next prime is 1010312631127. The reversal of 1010312631113 is 3111362130101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1010312631113 - 2² = 1010312631109 is a prime.

It is a super-4 number, since 4×1010312631113⁴ (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1010312631103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 150924743 + ... + 150931436.

It is an arithmetic number, because the mean of its divisors is an integer number (252653622660).

Almost surely, 2^{1010312631113} is an apocalyptic number.

It is an amenable number.

1010312631113 is a deficient number, since it is larger than the sum of its proper divisors (301859527).

1010312631113 is an equidigital number, since it uses as much as digits as its factorization.

1010312631113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 301859526.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 1010312631113 its reverse (3111362130101), we get a palindrome (4121674761214).

The spelling of 1010312631113 in words is "one trillion, ten billion, three hundred twelve million, six hundred thirty-one thousand, one hundred thirteen".