101043313201 has 4 divisors (see below), whose sum is σ = 101663210992. Its totient is φ = 100423415412.

The previous prime is 101043313193. The next prime is 101043313237. The reversal of 101043313201 is 102313340101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101043313201 - 2³ = 101043313193 is a prime.

It is a super-2 number, since 2×101043313201² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101043313291) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 309948651 + ... + 309948976.

It is an arithmetic number, because the mean of its divisors is an integer number (25415802748).

Almost surely, 2^101043313201 is an apocalyptic number.

It is an amenable number.

101043313201 is a deficient number, since it is larger than the sum of its proper divisors (619897791).

101043313201 is an equidigital number, since it uses as much as digits as its factorization.

101043313201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 619897790.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 101043313201 its reverse (102313340101), we get a palindrome (203356653302).

The spelling of 101043313201 in words is "one hundred one billion, forty-three million, three hundred thirteen thousand, two hundred one".