Search a number
-
+
101044131 = 341821497
BaseRepresentation
bin1100000010111…
…00111110100011
321001010120111020
412001130332203
5201331403011
614005420523
72334601206
oct601347643
9231116436
10101044131
1152044a51
1229a0a743
1317c1ab36
14d5c393d
158d0e006
hex605cfa3

101044131 has 8 divisors (see below), whose sum is σ = 138011664. Its totient is φ = 65719680.

The previous prime is 101044127. The next prime is 101044169. The reversal of 101044131 is 131440101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 101044131 - 22 = 101044127 is a prime.

It is a super-2 number, since 2×1010441312 = 20419832819090322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101044131.

It is not an unprimeable number, because it can be changed into a prime (101044231) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 410626 + ... + 410871.

It is an arithmetic number, because the mean of its divisors is an integer number (17251458).

Almost surely, 2101044131 is an apocalyptic number.

101044131 is a deficient number, since it is larger than the sum of its proper divisors (36967533).

101044131 is an equidigital number, since it uses as much as digits as its factorization.

101044131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 821541.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 101044131 is about 10052.0709806487. The cubic root of 101044131 is about 465.7687687872.

Adding to 101044131 its reverse (131440101), we get a palindrome (232484232).

The spelling of 101044131 in words is "one hundred one million, forty-four thousand, one hundred thirty-one".

Divisors: 1 3 41 123 821497 2464491 33681377 101044131