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101057143315 = 520211428663
BaseRepresentation
bin101111000011101111…
…0011010001000010011
3100122211211211210020211
41132013132122020103
53123431112041230
6114231445144551
710205201354662
oct1360736321023
9318754753224
10101057143315
1139949139567
12177039bb157
1396b683652b
144c69604dd9
152966e5742a
hex178779a213

101057143315 has 4 divisors (see below), whose sum is σ = 121268571984. Its totient is φ = 80845714648.

The previous prime is 101057143303. The next prime is 101057143333. The reversal of 101057143315 is 513341750101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 513341750101 = 571189886491.

It is a cyclic number.

It is not a de Polignac number, because 101057143315 - 221 = 101055046163 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10105714327 + ... + 10105714336.

It is an arithmetic number, because the mean of its divisors is an integer number (30317142996).

Almost surely, 2101057143315 is an apocalyptic number.

101057143315 is a deficient number, since it is larger than the sum of its proper divisors (20211428669).

101057143315 is an equidigital number, since it uses as much as digits as its factorization.

101057143315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20211428668.

The product of its (nonzero) digits is 6300, while the sum is 31.

Adding to 101057143315 its reverse (513341750101), we get a palindrome (614398893416).

The spelling of 101057143315 in words is "one hundred one billion, fifty-seven million, one hundred forty-three thousand, three hundred fifteen".

Divisors: 1 5 20211428663 101057143315