10110021120011 has 4 divisors (see below), whose sum is σ = 10110029472000. Its totient is φ = 10110012768024.

The previous prime is 10110021119981. The next prime is 10110021120013. The reversal of 10110021120011 is 11002112001101.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10110021120011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10110021119974 and 10110021120001.

It is not an unprimeable number, because it can be changed into a prime (10110021120013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1972796 + ... + 4910393.

It is an arithmetic number, because the mean of its divisors is an integer number (2527507368000).

Almost surely, 2^{10110021120011} is an apocalyptic number.

10110021120011 is a deficient number, since it is larger than the sum of its proper divisors (8351989).

10110021120011 is an equidigital number, since it uses as much as digits as its factorization.

10110021120011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8351988.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10110021120011 its reverse (11002112001101), we get a palindrome (21112133121112).

The spelling of 10110021120011 in words is "ten trillion, one hundred ten billion, twenty-one million, one hundred twenty thousand, eleven".