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10110243331 = 233111413427
BaseRepresentation
bin10010110101001111…
…00001001000000011
3222002121012120112201
421122213201020003
5131201210241311
64351121334031
7505353436036
oct113247411003
928077176481
1010110243331
114318a72501
121b61a97317
13c517a9506
146bca5d01d
153e28d79c1
hex25a9e1203

10110243331 has 8 divisors (see below), whose sum is σ = 10583748864. Its totient is φ = 9639565320.

The previous prime is 10110243329. The next prime is 10110243343. The reversal of 10110243331 is 13334201101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10110243331 - 21 = 10110243329 is a prime.

It is a super-2 number, since 2×101102433312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10110243299 and 10110243308.

It is not an unprimeable number, because it can be changed into a prime (10110243391) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 699561 + ... + 713866.

It is an arithmetic number, because the mean of its divisors is an integer number (1322968608).

Almost surely, 210110243331 is an apocalyptic number.

10110243331 is a deficient number, since it is larger than the sum of its proper divisors (473505533).

10110243331 is a wasteful number, since it uses less digits than its factorization.

10110243331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1413761.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10110243331 its reverse (13334201101), we get a palindrome (23444444432).

The spelling of 10110243331 in words is "ten billion, one hundred ten million, two hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 23 311 7153 1413427 32508821 439575797 10110243331