101104140113 has 4 divisors (see below), whose sum is σ = 101143806900. Its totient is φ = 101064473328.

The previous prime is 101104140097. The next prime is 101104140121. The reversal of 101104140113 is 311041401101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 60980845249 + 40123294864 = 246943^2 + 200308^2 .

It is a cyclic number.

It is not a de Polignac number, because 101104140113 - 2⁴ = 101104140097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101104140091 and 101104140100.

It is not an unprimeable number, because it can be changed into a prime (101104140413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19829570 + ... + 19834667.

It is an arithmetic number, because the mean of its divisors is an integer number (25285951725).

Almost surely, 2^101104140113 is an apocalyptic number.

It is an amenable number.

101104140113 is a deficient number, since it is larger than the sum of its proper divisors (39666787).

101104140113 is an equidigital number, since it uses as much as digits as its factorization.

101104140113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39666786.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101104140113 its reverse (311041401101), we get a palindrome (412145541214).

The spelling of 101104140113 in words is "one hundred one billion, one hundred four million, one hundred forty thousand, one hundred thirteen".