10111112020113 has 16 divisors (see below), whose sum is σ = 14528512004160. Its totient is φ = 6217940418624.

The previous prime is 10111112020099. The next prime is 10111112020123. The reversal of 10111112020113 is 31102021111101.

It is not a de Polignac number, because 10111112020113 - 2⁸ = 10111112019857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10111112020092 and 10111112020101.

It is not an unprimeable number, because it can be changed into a prime (10111112020123) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89158503 + ... + 89271836.

It is an arithmetic number, because the mean of its divisors is an integer number (908032000260).

Almost surely, 2^{10111112020113} is an apocalyptic number.

10111112020113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10111112020113 is a deficient number, since it is larger than the sum of its proper divisors (4417399984047).

10111112020113 is a wasteful number, since it uses less digits than its factorization.

10111112020113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 178431808.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 10111112020113 its reverse (31102021111101), we get a palindrome (41213133131214).

The spelling of 10111112020113 in words is "ten trillion, one hundred eleven billion, one hundred twelve million, twenty thousand, one hundred thirteen".