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101112101131 = 475012128631
BaseRepresentation
bin101111000101011000…
…0000011100100001011
3100122222200020221012111
41132022300003210023
53124034144214011
6114241131123151
710206436451566
oct1361260034413
9318880227174
10101112101131
1139977166148
121771a2a34b7
1396c5039452
144c72a2d4dd
15296bbb1121
hex178ac0390b

101112101131 has 4 divisors (see below), whose sum is σ = 101114277264. Its totient is φ = 101109925000.

The previous prime is 101112101119. The next prime is 101112101137. The reversal of 101112101131 is 131101211101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101112101131 - 27 = 101112101003 is a prime.

It is a super-2 number, since 2×1011121011312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101112101137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1016815 + ... + 1111816.

It is an arithmetic number, because the mean of its divisors is an integer number (25278569316).

Almost surely, 2101112101131 is an apocalyptic number.

101112101131 is a deficient number, since it is larger than the sum of its proper divisors (2176133).

101112101131 is an equidigital number, since it uses as much as digits as its factorization.

101112101131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2176132.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101112101131 its reverse (131101211101), we get a palindrome (232213312232).

The spelling of 101112101131 in words is "one hundred one billion, one hundred twelve million, one hundred one thousand, one hundred thirty-one".

Divisors: 1 47501 2128631 101112101131