1011130213313 has 4 divisors (see below), whose sum is σ = 1103051141808. Its totient is φ = 919209284820.

The previous prime is 1011130213283. The next prime is 1011130213319. The reversal of 1011130213313 is 3133120311101.

1011130213313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011130213313 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1011130213319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45960464231 + ... + 45960464252.

It is an arithmetic number, because the mean of its divisors is an integer number (275762785452).

Almost surely, 2^{1011130213313} is an apocalyptic number.

It is an amenable number.

1011130213313 is a deficient number, since it is larger than the sum of its proper divisors (91920928495).

1011130213313 is an equidigital number, since it uses as much as digits as its factorization.

1011130213313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91920928494.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1011130213313 its reverse (3133120311101), we get a palindrome (4144250524414).

The spelling of 1011130213313 in words is "one trillion, eleven billion, one hundred thirty million, two hundred thirteen thousand, three hundred thirteen".