10111310233121 has 4 divisors (see below), whose sum is σ = 10171857001152. Its totient is φ = 10050763465092.

The previous prime is 10111310233111. The next prime is 10111310233151. The reversal of 10111310233121 is 12133201311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10111310233121 - 2¹⁴ = 10111310216737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10111310233093 and 10111310233102.

It is not an unprimeable number, because it can be changed into a prime (10111310233111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30273383765 + ... + 30273384098.

It is an arithmetic number, because the mean of its divisors is an integer number (2542964250288).

Almost surely, 2^{10111310233121} is an apocalyptic number.

It is an amenable number.

10111310233121 is a deficient number, since it is larger than the sum of its proper divisors (60546768031).

10111310233121 is an equidigital number, since it uses as much as digits as its factorization.

10111310233121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60546768030.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 10111310233121 its reverse (12133201311101), we get a palindrome (22244511544222).

The spelling of 10111310233121 in words is "ten trillion, one hundred eleven billion, three hundred ten million, two hundred thirty-three thousand, one hundred twenty-one".