101113110121 has 4 divisors (see below), whose sum is σ = 101135669392. Its totient is φ = 101090550852.

The previous prime is 101113110113. The next prime is 101113110149. The reversal of 101113110121 is 121011311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 121011311101 = 58567 ⋅2066203.

It is a cyclic number.

It is not a de Polignac number, because 101113110121 - 2³ = 101113110113 is a prime.

It is a super-2 number, since 2×101113110121² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101113110151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11272911 + ... + 11281876.

It is an arithmetic number, because the mean of its divisors is an integer number (25283917348).

Almost surely, 2^101113110121 is an apocalyptic number.

It is an amenable number.

101113110121 is a deficient number, since it is larger than the sum of its proper divisors (22559271).

101113110121 is an equidigital number, since it uses as much as digits as its factorization.

101113110121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22559270.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101113110121 its reverse (121011311101), we get a palindrome (222124421222).

The spelling of 101113110121 in words is "one hundred one billion, one hundred thirteen million, one hundred ten thousand, one hundred twenty-one".