101113113121 has 4 divisors (see below), whose sum is σ = 103464580912. Its totient is φ = 98761645332.

The previous prime is 101113113119. The next prime is 101113113163. The reversal of 101113113121 is 121311311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101113113121 - 2¹ = 101113113119 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101113113095 and 101113113104.

It is not an unprimeable number, because it can be changed into a prime (101113116121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1175733831 + ... + 1175733916.

It is an arithmetic number, because the mean of its divisors is an integer number (25866145228).

Almost surely, 2^101113113121 is an apocalyptic number.

It is an amenable number.

101113113121 is a deficient number, since it is larger than the sum of its proper divisors (2351467791).

101113113121 is an equidigital number, since it uses as much as digits as its factorization.

101113113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2351467790.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 101113113121 its reverse (121311311101), we get a palindrome (222424424222).

The spelling of 101113113121 in words is "one hundred one billion, one hundred thirteen million, one hundred thirteen thousand, one hundred twenty-one".