1011134335203 has 6 divisors (see below), whose sum is σ = 1460527373084. Its totient is φ = 674089556796.

The previous prime is 1011134335193. The next prime is 1011134335207. The reversal of 1011134335203 is 3025334311101.

1011134335203 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 134 + 3 + 3 + 520 + 3 = 666.

It is not a de Polignac number, because 1011134335203 - 2¹² = 1011134331107 is a prime.

It is a super-3 number, since 3×1011134335203³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1011134335207) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 56174129725 + ... + 56174129742.

Almost surely, 2^{1011134335203} is an apocalyptic number.

1011134335203 is a deficient number, since it is larger than the sum of its proper divisors (449393037881).

1011134335203 is a wasteful number, since it uses less digits than its factorization.

1011134335203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112348259473 (or 112348259470 counting only the distinct ones).

The product of its (nonzero) digits is 3240, while the sum is 27.

Adding to 1011134335203 its reverse (3025334311101), we get a palindrome (4036468646304).

The spelling of 1011134335203 in words is "one trillion, eleven billion, one hundred thirty-four million, three hundred thirty-five thousand, two hundred three".