101120014303131 has 8 divisors (see below), whose sum is σ = 135363843849024. Its totient is φ = 67144763813000.

The previous prime is 101120014303097. The next prime is 101120014303163. The reversal of 101120014303131 is 131303410021101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101120014303131 - 2¹³ = 101120014294939 is a prime.

It is a super-2 number, since 2×101120014303131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101120014303098 and 101120014303107.

It is not an unprimeable number, because it can be changed into a prime (101120014303181) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67144763061 + ... + 67144764566.

It is an arithmetic number, because the mean of its divisors is an integer number (16920480481128).

Almost surely, 2^{101120014303131} is an apocalyptic number.

101120014303131 is a deficient number, since it is larger than the sum of its proper divisors (34243829545893).

101120014303131 is a wasteful number, since it uses less digits than its factorization.

101120014303131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 134289527881.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 101120014303131 its reverse (131303410021101), we get a palindrome (232423424324232).

The spelling of 101120014303131 in words is "one hundred one trillion, one hundred twenty billion, fourteen million, three hundred three thousand, one hundred thirty-one".