101120033331131 has 4 divisors (see below), whose sum is σ = 101185568026992. Its totient is φ = 101054498635272.

The previous prime is 101120033331101. The next prime is 101120033331193. The reversal of 101120033331131 is 131133330021101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101120033331131 - 2¹⁸ = 101120033068987 is a prime.

It is a super-2 number, since 2×101120033331131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101120033331097 and 101120033331106.

It is not an unprimeable number, because it can be changed into a prime (101120033331101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32767345616 + ... + 32767348701.

It is an arithmetic number, because the mean of its divisors is an integer number (25296392006748).

Almost surely, 2^{101120033331131} is an apocalyptic number.

101120033331131 is a deficient number, since it is larger than the sum of its proper divisors (65534695861).

101120033331131 is an equidigital number, since it uses as much as digits as its factorization.

101120033331131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65534695860.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 101120033331131 its reverse (131133330021101), we get a palindrome (232253363352232).

The spelling of 101120033331131 in words is "one hundred one trillion, one hundred twenty billion, thirty-three million, three hundred thirty-one thousand, one hundred thirty-one".