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101121024113 = 290173484889
BaseRepresentation
bin101111000101101001…
…0000110000001110001
3100200000022001021020022
41132023102012001301
53124043440232423
6114242050253225
710206605344244
oct1361322060161
9320008037208
10101121024113
113998120010a
1217721287215
1396c6b41a15
144c73cb325b
15296c874dc8
hex178b486071

101121024113 has 4 divisors (see below), whose sum is σ = 101124538020. Its totient is φ = 101117510208.

The previous prime is 101121024107. The next prime is 101121024131. The reversal of 101121024113 is 311420121101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 39534164224 + 61586859889 = 198832^2 + 248167^2 .

It is a cyclic number.

It is not a de Polignac number, because 101121024113 - 218 = 101120761969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101121024091 and 101121024100.

It is not an unprimeable number, because it can be changed into a prime (101121024313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1713428 + ... + 1771461.

It is an arithmetic number, because the mean of its divisors is an integer number (25281134505).

Almost surely, 2101121024113 is an apocalyptic number.

It is an amenable number.

101121024113 is a deficient number, since it is larger than the sum of its proper divisors (3513907).

101121024113 is an equidigital number, since it uses as much as digits as its factorization.

101121024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3513906.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 101121024113 its reverse (311420121101), we get a palindrome (412541145214).

The spelling of 101121024113 in words is "one hundred one billion, one hundred twenty-one million, twenty-four thousand, one hundred thirteen".

Divisors: 1 29017 3484889 101121024113