10112110002011 has 4 divisors (see below), whose sum is σ = 10132704931224. Its totient is φ = 10091515072800.

The previous prime is 10112110001993. The next prime is 10112110002017. The reversal of 10112110002011 is 11020001121101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10112110002011 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10112110001983 and 10112110002001.

It is not an unprimeable number, because it can be changed into a prime (10112110002017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10297463870 + ... + 10297464851.

It is an arithmetic number, because the mean of its divisors is an integer number (2533176232806).

Almost surely, 2^{10112110002011} is an apocalyptic number.

10112110002011 is a deficient number, since it is larger than the sum of its proper divisors (20594929213).

10112110002011 is an equidigital number, since it uses as much as digits as its factorization.

10112110002011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20594929212.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 10112110002011 its reverse (11020001121101), we get a palindrome (21132111123112).

The spelling of 10112110002011 in words is "ten trillion, one hundred twelve billion, one hundred ten million, two thousand, eleven".