101121231403 has 4 divisors (see below), whose sum is σ = 101121887560. Its totient is φ = 101120575248.

The previous prime is 101121231397. The next prime is 101121231481. The reversal of 101121231403 is 304132121101.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 304132121101 = 16451 ⋅18487151.

It is a cyclic number.

It is not a de Polignac number, because 101121231403 - 2¹³ = 101121223211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101121238403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42976 + ... + 451762.

It is an arithmetic number, because the mean of its divisors is an integer number (25280471890).

Almost surely, 2^101121231403 is an apocalyptic number.

101121231403 is a deficient number, since it is larger than the sum of its proper divisors (656157).

101121231403 is an equidigital number, since it uses as much as digits as its factorization.

101121231403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656156.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 101121231403 its reverse (304132121101), we get a palindrome (405253352504).

The spelling of 101121231403 in words is "one hundred one billion, one hundred twenty-one million, two hundred thirty-one thousand, four hundred three".