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1011213130433 = 111940813118549
BaseRepresentation
bin11101011011100001111…
…11111101101011000001
310120200010011220110201012
432231300333331223001
5113031431030133213
62052313410450305
7133025542534262
oct16556077755301
93520104813635
101011213130433
1135a9424a4840
12143b91293995
13744843c6b6c
1436d2b756969
151b485da54a8
hexeb70ffdac1

1011213130433 has 16 divisors (see below), whose sum is σ = 1161239928000. Its totient is φ = 870872575680.

The previous prime is 1011213130427. The next prime is 1011213130441. The reversal of 1011213130433 is 3340313121101.

It is not a de Polignac number, because 1011213130433 - 232 = 1006918163137 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011213130399 and 1011213130408.

It is not an unprimeable number, because it can be changed into a prime (1011213135433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8470643 + ... + 8589191.

It is an arithmetic number, because the mean of its divisors is an integer number (72577495500).

Almost surely, 21011213130433 is an apocalyptic number.

It is an amenable number.

1011213130433 is a deficient number, since it is larger than the sum of its proper divisors (150026797567).

1011213130433 is a wasteful number, since it uses less digits than its factorization.

1011213130433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159392.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1011213130433 its reverse (3340313121101), we get a palindrome (4351526251534).

The spelling of 1011213130433 in words is "one trillion, eleven billion, two hundred thirteen million, one hundred thirty thousand, four hundred thirty-three".

Divisors: 1 11 19 209 40813 118549 448943 775447 1304039 2252431 8529917 24776741 4838340337 53221743707 91928466403 1011213130433