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101121330131 = 101999235849
BaseRepresentation
bin101111000101101001…
…1010000101111010011
3100200000022121211000022
41132023103100233103
53124044030031011
6114242101014055
710206611060363
oct1361323205723
9320008554008
10101121330131
113998139a018
12177213b432b
1396c6c1b0b3
144c73d529a3
15296c8d58db
hex178b4d0bd3

101121330131 has 4 divisors (see below), whose sum is σ = 101220567000. Its totient is φ = 101022093264.

The previous prime is 101121330119. The next prime is 101121330221. The reversal of 101121330131 is 131033121101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101121330131 is a prime.

It is a super-2 number, since 2×1011213301312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101121330031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49616906 + ... + 49618943.

It is an arithmetic number, because the mean of its divisors is an integer number (25305141750).

Almost surely, 2101121330131 is an apocalyptic number.

101121330131 is a deficient number, since it is larger than the sum of its proper divisors (99236869).

101121330131 is an equidigital number, since it uses as much as digits as its factorization.

101121330131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99236868.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 101121330131 its reverse (131033121101), we get a palindrome (232154451232).

The spelling of 101121330131 in words is "one hundred one billion, one hundred twenty-one million, three hundred thirty thousand, one hundred thirty-one".

Divisors: 1 1019 99235849 101121330131