Base | Representation |
---|---|
bin | 1001001100100111010011… |
… | …0001010111011101101011 |
3 | 1022210201122102021201222101 |
4 | 2103021310301113131223 |
5 | 2311140003400104003 |
6 | 33301310531234231 |
7 | 2062406343506062 |
oct | 223116461273553 |
9 | 38721572251871 |
10 | 10112312113003 |
11 | 3249675618921 |
12 | 1173a00a48977 |
13 | 58478267bb19 |
14 | 26d61d4151d9 |
15 | 1280a000111d |
hex | 93274c5776b |
10112312113003 has 4 divisors (see below), whose sum is σ = 10121580961128. Its totient is φ = 10103043264880.
The previous prime is 10112312112997. The next prime is 10112312113067. The reversal of 10112312113003 is 30031121321101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10112312113003 - 221 = 10112310015851 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10112312113103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4634422426 + ... + 4634424607.
It is an arithmetic number, because the mean of its divisors is an integer number (2530395240282).
Almost surely, 210112312113003 is an apocalyptic number.
10112312113003 is a deficient number, since it is larger than the sum of its proper divisors (9268848125).
10112312113003 is an equidigital number, since it uses as much as digits as its factorization.
10112312113003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9268848124.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 10112312113003 its reverse (30031121321101), we get a palindrome (40143433434104).
The spelling of 10112312113003 in words is "ten trillion, one hundred twelve billion, three hundred twelve million, one hundred thirteen thousand, three".
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