101123143242401 has 4 divisors (see below), whose sum is σ = 115569306562752. Its totient is φ = 86676979922052.

The previous prime is 101123143242367. The next prime is 101123143242409. The reversal of 101123143242401 is 104242341321101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101123143242401 is a prime.

It is not an unprimeable number, because it can be changed into a prime (101123143242409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7223081660165 + ... + 7223081660178.

It is an arithmetic number, because the mean of its divisors is an integer number (28892326640688).

Almost surely, 2^{101123143242401} is an apocalyptic number.

It is an amenable number.

101123143242401 is a deficient number, since it is larger than the sum of its proper divisors (14446163320351).

101123143242401 is an equidigital number, since it uses as much as digits as its factorization.

101123143242401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14446163320350.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 101123143242401 its reverse (104242341321101), we get a palindrome (205365484563502).

The spelling of 101123143242401 in words is "one hundred one trillion, one hundred twenty-three billion, one hundred forty-three million, two hundred forty-two thousand, four hundred one".