101124400433 has 4 divisors (see below), whose sum is σ = 115570743360. Its totient is φ = 86678057508.

The previous prime is 101124400427. The next prime is 101124400561. The reversal of 101124400433 is 334004421101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 101124400433 - 2⁴ = 101124400417 is a prime.

It is a super-3 number, since 3×101124400433³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101124400399 and 101124400408.

It is not an unprimeable number, because it can be changed into a prime (101124400933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7223171453 + ... + 7223171466.

It is an arithmetic number, because the mean of its divisors is an integer number (28892685840).

Almost surely, 2^101124400433 is an apocalyptic number.

It is an amenable number.

101124400433 is a deficient number, since it is larger than the sum of its proper divisors (14446342927).

101124400433 is an equidigital number, since it uses as much as digits as its factorization.

101124400433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14446342926.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 101124400433 its reverse (334004421101), we get a palindrome (435128821534).

The spelling of 101124400433 in words is "one hundred one billion, one hundred twenty-four million, four hundred thousand, four hundred thirty-three".