1011244341131 has 4 divisors (see below), whose sum is σ = 1070729302392. Its totient is φ = 951759379872.

The previous prime is 1011244341127. The next prime is 1011244341193. The reversal of 1011244341131 is 1311434421101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1011244341131 - 2² = 1011244341127 is a prime.

It is a super-2 number, since 2×1011244341131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011244341131.

It is not an unprimeable number, because it can be changed into a prime (1011244340131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29742480605 + ... + 29742480638.

It is an arithmetic number, because the mean of its divisors is an integer number (267682325598).

Almost surely, 2^{1011244341131} is an apocalyptic number.

1011244341131 is a deficient number, since it is larger than the sum of its proper divisors (59484961261).

1011244341131 is an equidigital number, since it uses as much as digits as its factorization.

1011244341131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59484961260.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 1011244341131 its reverse (1311434421101), we get a palindrome (2322678762232).

The spelling of 1011244341131 in words is "one trillion, eleven billion, two hundred forty-four million, three hundred forty-one thousand, one hundred thirty-one".