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101130003 = 3213864359
BaseRepresentation
bin1100000011100…
…01111100010011
321001021221021200
412001301330103
5201342130003
614011322243
72335406442
oct601617423
9231257250
10101130003
11520a3517
1229a50383
1317c4ac50
14d606d59
158d296a3
hex6071f13

101130003 has 12 divisors (see below), whose sum is σ = 157313520. Its totient is φ = 62233776.

The previous prime is 101129999. The next prime is 101130017. The reversal of 101130003 is 300031101.

It is not a de Polignac number, because 101130003 - 22 = 101129999 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (9).

It is not an unprimeable number, because it can be changed into a prime (101130053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 432063 + ... + 432296.

It is an arithmetic number, because the mean of its divisors is an integer number (13109460).

Almost surely, 2101130003 is an apocalyptic number.

101130003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

101130003 is a deficient number, since it is larger than the sum of its proper divisors (56183517).

101130003 is a wasteful number, since it uses less digits than its factorization.

101130003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 864378 (or 864375 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 9.

The square root of 101130003 is about 10056.3414321512. The cubic root of 101130003 is about 465.9006754118.

Adding to 101130003 its reverse (300031101), we get a palindrome (401161104).

The spelling of 101130003 in words is "one hundred one million, one hundred thirty thousand, three".

Divisors: 1 3 9 13 39 117 864359 2593077 7779231 11236667 33710001 101130003