Base | Representation |
---|---|
bin | 11101011011101100011… |
… | …00001100000110001011 |
3 | 10120200100020210010221201 |
4 | 32231312030030012023 |
5 | 113032120324040243 |
6 | 2052330201245031 |
7 | 133030651022500 |
oct | 16556614140613 |
9 | 3520306703851 |
10 | 1011300221323 |
11 | 35a987679487 |
12 | 143bb6493777 |
13 | 7449946a932 |
14 | 36d391474a7 |
15 | 1b48d85a04d |
hex | eb7630c18b |
1011300221323 has 12 divisors (see below), whose sum is σ = 1179127369560. Its totient is φ = 864826828992.
The previous prime is 1011300221299. The next prime is 1011300221339. The reversal of 1011300221323 is 3231220031101.
1011300221323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1011300221323 - 25 = 1011300221291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1011300221323.
It is not an unprimeable number, because it can be changed into a prime (1011300221023) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 23811093 + ... + 23853526.
It is an arithmetic number, because the mean of its divisors is an integer number (98260614130).
Almost surely, 21011300221323 is an apocalyptic number.
1011300221323 is a deficient number, since it is larger than the sum of its proper divisors (167827148237).
1011300221323 is an equidigital number, since it uses as much as digits as its factorization.
1011300221323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47665066 (or 47665059 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 1011300221323 its reverse (3231220031101), we get a palindrome (4242520252424).
The spelling of 1011300221323 in words is "one trillion, eleven billion, three hundred million, two hundred twenty-one thousand, three hundred twenty-three".
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