1011301414131 has 8 divisors (see below), whose sum is σ = 1348408131840. Its totient is φ = 674197819592.

The previous prime is 1011301414111. The next prime is 1011301414133. The reversal of 1011301414131 is 1314141031101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1011301414131 - 2⁵ = 1011301414099 is a prime.

It is a super-2 number, since 2×1011301414131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1011301414098 and 1011301414107.

It is not an unprimeable number, because it can be changed into a prime (1011301414133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 124810 + ... + 1427648.

It is an arithmetic number, because the mean of its divisors is an integer number (168551016480).

Almost surely, 2^{1011301414131} is an apocalyptic number.

1011301414131 is a deficient number, since it is larger than the sum of its proper divisors (337106717709).

1011301414131 is a wasteful number, since it uses less digits than its factorization.

1011301414131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1561585.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 1011301414131 its reverse (1314141031101), we get a palindrome (2325442445232).

The spelling of 1011301414131 in words is "one trillion, eleven billion, three hundred one million, four hundred fourteen thousand, one hundred thirty-one".