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101130624433 = 234396983671
BaseRepresentation
bin101111000101111011…
…0101101110110110001
3100200000222010000101201
41132023312231312301
53124103414440213
6114243032131201
710210053060436
oct1361366556661
9320028100351
10101130624433
1139986667a63
1217724536b01
1396c8b23697
144c75291b8d
15296d61e6dd
hex178bdaddb1

101130624433 has 4 divisors (see below), whose sum is σ = 105527608128. Its totient is φ = 96733640740.

The previous prime is 101130624421. The next prime is 101130624443. The reversal of 101130624433 is 334426031101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101130624433 - 217 = 101130493361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101130624443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2198491813 + ... + 2198491858.

It is an arithmetic number, because the mean of its divisors is an integer number (26381902032).

Almost surely, 2101130624433 is an apocalyptic number.

It is an amenable number.

101130624433 is a deficient number, since it is larger than the sum of its proper divisors (4396983695).

101130624433 is an equidigital number, since it uses as much as digits as its factorization.

101130624433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4396983694.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 101130624433 its reverse (334426031101), we get a palindrome (435556655534).

The spelling of 101130624433 in words is "one hundred one billion, one hundred thirty million, six hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 23 4396983671 101130624433