101131100023113 has 12 divisors (see below), whose sum is σ = 152429484093120. Its totient is φ = 64489397116056.

The previous prime is 101131100023103. The next prime is 101131100023127. The reversal of 101131100023113 is 311320001131101.

It is not a de Polignac number, because 101131100023113 - 2¹⁰ = 101131100022089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101131100023103) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 244278019173 + ... + 244278019586.

It is an arithmetic number, because the mean of its divisors is an integer number (12702457007760).

Almost surely, 2^{101131100023113} is an apocalyptic number.

It is an amenable number.

101131100023113 is a deficient number, since it is larger than the sum of its proper divisors (51298384070007).

101131100023113 is a wasteful number, since it uses less digits than its factorization.

101131100023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 488556038788 (or 488556038785 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 101131100023113 its reverse (311320001131101), we get a palindrome (412451101154214).

The spelling of 101131100023113 in words is "one hundred one trillion, one hundred thirty-one billion, one hundred million, twenty-three thousand, one hundred thirteen".