Base | Representation |
---|---|
bin | 1001001100101010010100… |
… | …0111011101111110011011 |
3 | 1022210210201221111220021211 |
4 | 2103022211013131332123 |
5 | 2311143134020310321 |
6 | 33301523224043551 |
7 | 2062435422653524 |
oct | 223124507357633 |
9 | 38723657456254 |
10 | 10113123213211 |
11 | 3249a51450477 |
12 | 1173ba86035b7 |
13 | 58488171a285 |
14 | 26d69902d84b |
15 | 1280eb31c0e1 |
hex | 932a51ddf9b |
10113123213211 has 4 divisors (see below), whose sum is σ = 10113412699000. Its totient is φ = 10112833727424.
The previous prime is 10113123213203. The next prime is 10113123213223. The reversal of 10113123213211 is 11231232131101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10113123213211 - 23 = 10113123213203 is a prime.
It is a super-2 number, since 2×101131232132112 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10113123211211) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 144690486 + ... + 144760363.
It is an arithmetic number, because the mean of its divisors is an integer number (2528353174750).
Almost surely, 210113123213211 is an apocalyptic number.
10113123213211 is a deficient number, since it is larger than the sum of its proper divisors (289485789).
10113123213211 is an equidigital number, since it uses as much as digits as its factorization.
10113123213211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 289485788.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 10113123213211 its reverse (11231232131101), we get a palindrome (21344355344312).
The spelling of 10113123213211 in words is "ten trillion, one hundred thirteen billion, one hundred twenty-three million, two hundred thirteen thousand, two hundred eleven".
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