1011314040113 has 4 divisors (see below), whose sum is σ = 1089107427828. Its totient is φ = 933520652400.

The previous prime is 1011314040109. The next prime is 1011314040133. The reversal of 1011314040113 is 3110404131101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 563554994209 + 447759045904 = 750703^2 + 669148^2 .

It is a cyclic number.

It is not a de Polignac number, because 1011314040113 - 2² = 1011314040109 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1011314040133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38896693838 + ... + 38896693863.

It is an arithmetic number, because the mean of its divisors is an integer number (272276856957).

Almost surely, 2^{1011314040113} is an apocalyptic number.

1011314040113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1011314040113 is a deficient number, since it is larger than the sum of its proper divisors (77793387715).

1011314040113 is an equidigital number, since it uses as much as digits as its factorization.

1011314040113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77793387714.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1011314040113 its reverse (3110404131101), we get a palindrome (4121718171214).

The spelling of 1011314040113 in words is "one trillion, eleven billion, three hundred fourteen million, forty thousand, one hundred thirteen".