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101131450001 = 283357354947
BaseRepresentation
bin101111000101111100…
…1110111011010010001
3100200001000122221212022
41132023321313122101
53124104122400001
6114243101541225
710210063066361
oct1361371673221
9320030587768
10101131450001
113998708124a
1217724874815
1396c905239a
144c754289a1
15296d73411b
hex178be77691

101131450001 has 4 divisors (see below), whose sum is σ = 101488805232. Its totient is φ = 100774094772.

The previous prime is 101131449983. The next prime is 101131450019. The reversal of 101131450001 is 100054131101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (101131449983) and next prime (101131450019).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101131450001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101131450061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 178677191 + ... + 178677756.

It is an arithmetic number, because the mean of its divisors is an integer number (25372201308).

Almost surely, 2101131450001 is an apocalyptic number.

It is an amenable number.

101131450001 is a deficient number, since it is larger than the sum of its proper divisors (357355231).

101131450001 is an equidigital number, since it uses as much as digits as its factorization.

101131450001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 357355230.

The product of its (nonzero) digits is 60, while the sum is 17.

Adding to 101131450001 its reverse (100054131101), we get a palindrome (201185581102).

The spelling of 101131450001 in words is "one hundred one billion, one hundred thirty-one million, four hundred fifty thousand, one".

Divisors: 1 283 357354947 101131450001