10113220123 has 4 divisors (see below), whose sum is σ = 10114130248. Its totient is φ = 10112310000.

The previous prime is 10113220111. The next prime is 10113220133. The reversal of 10113220123 is 32102231101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10113220123 - 2³³ = 1523285531 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10113220097 and 10113220106.

It is not an unprimeable number, because it can be changed into a prime (10113220133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 438186 + ... + 460687.

It is an arithmetic number, because the mean of its divisors is an integer number (2528532562).

Almost surely, 2^10113220123 is an apocalyptic number.

10113220123 is a deficient number, since it is larger than the sum of its proper divisors (910125).

10113220123 is an equidigital number, since it uses as much as digits as its factorization.

10113220123 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 910124.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10113220123 its reverse (32102231101), we get a palindrome (42215451224).

The spelling of 10113220123 in words is "ten billion, one hundred thirteen million, two hundred twenty thousand, one hundred twenty-three".