10113301113 has 4 divisors (see below), whose sum is σ = 13484401488. Its totient is φ = 6742200740.

The previous prime is 10113301103. The next prime is 10113301117. The reversal of 10113301113 is 31110331101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113301113 - 2¹⁰ = 10113300089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10113301092 and 10113301101.

It is not an unprimeable number, because it can be changed into a prime (10113301117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685550183 + ... + 1685550188.

It is an arithmetic number, because the mean of its divisors is an integer number (3371100372).

Almost surely, 2^10113301113 is an apocalyptic number.

It is an amenable number.

10113301113 is a deficient number, since it is larger than the sum of its proper divisors (3371100375).

10113301113 is an equidigital number, since it uses as much as digits as its factorization.

10113301113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3371100374.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 10113301113 its reverse (31110331101), we get a palindrome (41223632214).

The spelling of 10113301113 in words is "ten billion, one hundred thirteen million, three hundred one thousand, one hundred thirteen".