101133103110001 has 4 divisors (see below), whose sum is σ = 101163104033904. Its totient is φ = 101103102186100.

The previous prime is 101133103109989. The next prime is 101133103110023. The reversal of 101133103110001 is 100011301331101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101133103110001 - 2¹⁵ = 101133103077233 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101133103110101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15000456895 + ... + 15000463636.

It is an arithmetic number, because the mean of its divisors is an integer number (25290776008476).

Almost surely, 2^{101133103110001} is an apocalyptic number.

It is an amenable number.

101133103110001 is a deficient number, since it is larger than the sum of its proper divisors (30000923903).

101133103110001 is an equidigital number, since it uses as much as digits as its factorization.

101133103110001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30000923902.

The product of its (nonzero) digits is 27, while the sum is 16.

Adding to 101133103110001 its reverse (100011301331101), we get a palindrome (201144404441102).

The spelling of 101133103110001 in words is "one hundred one trillion, one hundred thirty-three billion, one hundred three million, one hundred ten thousand, one".